ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2019
  • Hard
  • MCQ

If Surface tension \((S)\), Moment of Inertia \((I)\) and Planck’s constant \((h)\), were to be taken as the fundamental units, the dimensional formula for linear momentum would be

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(S^{1 /2} I^{1 /2} h^0\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{l}
P = k\,{s^a}{i^b}{h^c}\\
Where\,k\,is\,{\rm{dimensionless}}\,{\rm{constant}}\\
ML{T^{ - 1}} = {\left( {M{T^{ - 2}}} \right)^a}\left( {M{L^2}} \right){\left( {M{L^2}{T^{ - 1}}} \right)^c}\\
a + b + c = 1\\
2b + 2c =  1\\
 - 2a - c =  - 1\\
a = \frac{1}{2}\,\,\,\,\,\,\,b = \frac{1}{2}\,\,\,\,\,\,c = 0\\
{S^{1/2}}{i^{1/2}}{h^0}
\end{array}\)
Same subject
Explore more questions on app