JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2021
- Hard
- Numerical
An unpolarized light beam is incident on the polarizer of a polarization experiment and the intensity of light beam emerging from the analyzer is measured as \(100\) Lumens. Now, if the analyzer is rotated around the horizontal axis (direction of light) by \(30^{\circ}\) in clockwise direction, the intensity of emerging light will be .......... Lumens.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(75\)
Step-by-step Solution
Detailed explanation
Now emerging intensity \(=\frac{ I _{0}}{2} \cos ^{2} 30^{\circ}\)
\(=100\left(\frac{\sqrt{3}}{2}\right)^{2}=100 \times \frac{3}{4}=75\)
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