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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2022
  • Medium
  • Numerical

In young's double slit experiment, the fringe width is \(12\,mm\). If the entire arrangement is placed in water of refractive index \(\frac{4}{3}\), then the fringe width becomes \((in\,mm)\)

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Correct Answer

(B) \(9\)

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Detailed explanation

For a given light wavelength corresponding a medium of refractive index \(\mu\)

\(\lambda_{\text {med }}=\frac{\lambda_{\text {vacuum }}}{\mu}\)

and we know that fringe width \(\beta=\frac{\lambda D}{ d }\)

Therefore, \(\beta_{\text {med }}=\frac{\beta_{\text {vacuum }}}{\mu}=\frac{12}{\frac{4}{3}}=9\,mm\)

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