JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2022
- Medium
- Numerical
In young's double slit experiment, the fringe width is \(12\,mm\). If the entire arrangement is placed in water of refractive index \(\frac{4}{3}\), then the fringe width becomes \((in\,mm)\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(9\)
Step-by-step Solution
Detailed explanation
For a given light wavelength corresponding a medium of refractive index \(\mu\)
\(\lambda_{\text {med }}=\frac{\lambda_{\text {vacuum }}}{\mu}\)
and we know that fringe width \(\beta=\frac{\lambda D}{ d }\)
Therefore, \(\beta_{\text {med }}=\frac{\beta_{\text {vacuum }}}{\mu}=\frac{12}{\frac{4}{3}}=9\,mm\)
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