JEE Mains · Physics · STD 12 - 10. Wave optics
In young's double slit experiment, the fringe width is \(12\,mm\). If the entire arrangement is placed in water of refractive index \(\frac{4}{3}\), then the fringe width becomes \((in\,mm)\)
- A \(16\)
- B \(9\)
- C \(48\)
- D \(12\)
Answer & Solution
Correct Answer
(B) \(9\)
Step-by-step Solution
Detailed explanation
For a given light wavelength corresponding a medium of refractive index \(\mu\) \(\lambda_{\text {med }}=\frac{\lambda_{\text {vacuum }}}{\mu}\) and we know that fringe width \(\beta=\frac{\lambda D}{ d }\) Therefore,…
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