JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor is having separation between plates \(0.885\) mm. It has a capacitance of \(1\,\mu\)F when the space between the plates is filled with an insulating material of resistivity \(1\times 10^{13}\,\Omega\)m and resistance \(17.7\times 10^{14}\,\Omega\). Relative permittivity of the insulating material is \(\alpha\times 10^7\). The value of \(\alpha\) is ________. (Take permittivity of free space \(=8.85\times 10^{-12}\) F/m)
- A 0
- B 2
- C 4
- D 6
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
The resistance of the insulating material is given by \(R = \dfrac{\rho d}{A}\). The capacitance of the parallel plate capacitor is given by \(C = \dfrac{\epsilon_0 \epsilon_r A}{d}\). Multiplying the expressions for \(R\) and \(C\), we get: \(RC = \rho \epsilon_0 \epsilon_r\)…
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