JEE Mains · Physics · STD 12 -7. Alternating current
The frequencies at which the current amplitude in an \(LCR\) series circuit becomes \(\frac{1}{\sqrt{2}}\) times its maximum value, are \(212\,rad\,s ^{-1}\) and \(232\,rad\,s ^{-1}\). The value of resistance in the circuit is \(R =5 \Omega\). The self inductance in the circuit is \(.........mH\)
- A \(250\)
- B \(2489\)
- C \(254\)
- D \(552\)
Answer & Solution
Correct Answer
(A) \(250\)
Step-by-step Solution
Detailed explanation
Band width \(=232-212=\frac{ R }{ L }\) \(\therefore L =\frac{5}{20}=250\,mH\)
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