JEE Mains · Physics · STD 12 - 10. Wave optics
In Young's double slit experiment, the fringe width of the interference pattern produced on the screen is \(2.4\) \(\mu\)m. If the experiment is carried out in another medium having refractive index \(1.2\), the fringe width will be _____ \(\mu\)m.
- A \(1.2\)
- B \(2\)
- C \(2.4\)
- D \(2.88\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
The fringe width in Young's double slit experiment is given by \(\beta = \dfrac{\lambda D}{d}\). When the experiment is performed in a medium of refractive index \(\mu\), the wavelength of light becomes \(\lambda' = \dfrac{\lambda}{\mu}\). The new fringe width is…
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