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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2024
  • Hard
  • MCQ

A block of mass \(1 \mathrm{~kg}\) is pushed up a surface inclined to horizontal at an angle of \(60^{\circ}\) by a force of \(10 \mathrm{~N}\) parallel to the inclined surface as shown in figure. When the block is pushed up by \(10 \mathrm{~m}\) along inclined surface, the work done against frictional force is _______. \(\left[\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right]\)

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Answer & Solution

Correct Answer

(B) \(5 \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

Work done against frictional force
\(=\mu \mathrm{N} \times 10\)
\(=0.1 \times 5 \times 10=5 \mathrm{~J}\)
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