JEE Mains · Physics · STD 12 - 3. current electricity
To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained If \(V_0\) is almost zero, identify the correct statement
- A The potential difference across the battery is \(1.5\, V\) when it sends a current of \(1000\, mA\)
- B The \(emf\) of the battery is \(1.5\, V\) and the value of \(R\) is \(1.5\,\Omega \)
- C The \(emf\) of the battery is \(1.5\, V\) and its internal resistance is \(1.5\,\Omega \)
- D The value of the resistance \(R\) is \(1.5\,\Omega \)
Answer & Solution
Correct Answer
(C) The \(emf\) of the battery is \(1.5\, V\) and its internal resistance is \(1.5\,\Omega \)
Step-by-step Solution
Detailed explanation
\(V=E-I r\) When \(V=V_{0}=0 \Rightarrow 0=E-I r\) \( \therefore\) \(E=r\) When \(1=0, V=E=1.5 \,\mathrm{V}\) \(\therefore r=1.5\, \Omega\)
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