JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
A Zener of breakdown voltage \(V_{z}=8\,V\) and maximum zener current, \(I _{ ZM }=10\,mA\) is subjected to an input voltage \(V _{ i }=10\,V\) with series resistance \(R=100\,\Omega\). In the given circuit \(R_{L}\) represents the variable load resistance. The ratio of maximum and minimum value of \(R_{L}\) is
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(I =\frac{2}{100}=20 mA\) \(V _{ L }= I _{ L } R _{ L }\) \(8=10 \times 10^{-3} \times R _{ L _{\max }}\) \(\frac{4}{5} \times 10^{3}= R _{ L _{\max }}\) \(800= R _{ L _{\max }}\) \(I = I _{ Z }+ I _{ L }\) \(I _{ L }=10 mA\) If \(I _{ Z }=0\) \(I _{ L _{\max }}=20 mA\)…
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