ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2021
  • Medium
  • Numerical

A heat engine operates between a cold reservoir at temperature \({T}_{2}=400\, {K}\) and a hot reservoir at temperature \({T}_{1} .\) It takes \(300 \,{J}\) of heat from the hot reservoir and delivers \(240\, {J}\) of heat to the cold reservoir in a cycle. The minimum temperature of the hot reservoir has to be \(....{K}\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(500\)

Step-by-step Solution

Detailed explanation

\({Q}_{\text {in }}=300\, {J} ; Q_{\text { out }}=240\, {J}\)

Work done \(=Q_{\text {in }}-Q_{\text {out }}=300-240=60 {J}\)

Efficiency \(=\frac{W}{{Q}_{\text {in }}}=\frac{60}{300}=\frac{1}{5}\)

efficiency \(=1-\frac{{T}_{2}}{{T}_{1}}\)

\(\frac{1}{5}=1-\frac{400}{{T}_{1}} \Rightarrow \frac{400}{{T}_{1}}=\frac{4}{5}\)

\({T}_{1}=500\, {k}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app