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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
A particle of mass \(4\, {M}\) at rest disintegrates into two particles of mass \({M}\) and \(3 \,{M}\) respectively having non zero velocities. The ratio of de-Broglie wavelength of particle of mass \(M\) to that of mass \(3\, {M}\) will be :
- A \(1: 3\)
- B \(3: 1\)
- C \(1: \sqrt3\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(D) \(1: 1\)
Step-by-step Solution
Detailed explanation
According to law of conservation of linear momentum, two particles will have equal and opposite momentum. The de Broglie wavelength is given by \(\lambda=\frac{ h }{ p } \quad \therefore \frac{\lambda_{1}}{\lambda_{2}}=1\)
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