JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Integrated rate law equation for a first order gas phase reaction is given by: (where \(P_i\) is initial pressure and \(P_t\) is total pressure at time \(t\) )
- A \(\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \log \frac{\mathrm{P}_{\mathrm{i}}}{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}\)
- B \(k=\frac{2.303}{t} \times \log \frac{2 P_i}{\left(2 P_i-P_t\right)}\)
- C \(k=\frac{2.303}{t} \times \log \frac{\left(2 P_i-P_t\right)}{P_i}\)
- D \(\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \frac{\mathrm{P}_{\mathrm{i}}}{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \log \frac{\mathrm{P}_{\mathrm{i}}}{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A} \rightarrow\) \(\mathrm{B}+\) \(\mathrm{C}\) \(P_i\) \(0\) \(0\) \(P_i-\) \(x\) \(x\) \(\mathrm{P}_{\mathrm{t}}=\mathrm{P}_{\mathrm{i}}+\mathrm{x}\) \(\mathrm{P}_{\mathrm{i}}-\mathrm{x}=\mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}+\mathrm{P}_{\mathrm{i}}\)…
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