JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Given at \(298\) K: \(E^{\ominus}_{Fe^{2+}/Fe} = X\) Volt; \(E^{\ominus}_{Fe^{3+}/Fe} = Y\) Volt. The \(E^{\ominus}_{Fe^{3+}/Fe^{2+}}\) in Volt at \(298\) K is given by:
- A \(2X-3Y\)
- B \(3Y-2X\)
- C \(3Y+2X\)
- D \(Y+X\)
Answer & Solution
Correct Answer
(B) \(3Y-2X\)
Step-by-step Solution
Detailed explanation
The half-reactions and their standard Gibbs free energy changes are given by: \(Fe^{2+} + 2e^{-} \rightarrow Fe\) \(\Delta G^{\ominus}_{1} = -2FX\) \(Fe^{3+} + 3e^{-} \rightarrow Fe\) \(\Delta G^{\ominus}_{2} = -3FY\) The required half-reaction is:…
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