JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Given below are two statements : Statement \(I\) : The rate law for the reaction \(A+B \rightarrow C\) is rate \((r)=k[A]^2[B]\). When the concentration of both \(\mathrm{A}\) and \(\mathrm{B}\) is doubled, the reaction rate is increased " \(\mathrm{x}\) " times. Statement \(II\) : (Image) The figure is showing "the variation in concentration against time plot" for a \("y"\) order reaction. The value of \(x+y\) is _______.

- A \(7\)
- B \(8\)
- C \(10\)
- D \(15\)
Answer & Solution
Correct Answer
(B) \(8\)
Step-by-step Solution
Detailed explanation
\(\mathrm{r}=\mathrm{K}[\mathrm{A}]^2|\mathrm{~B}|\) if conc. are doubled \(\mathrm{r}^{\prime}=\mathrm{K}[2 \mathrm{~A}]^2[2 \mathrm{~B}]^1\) \(\mathrm{r}^{\prime}=8 \mathrm{r} \Rightarrow \mathrm{x}=8\) (Image) \(\Rightarrow \text { Zero order, } y=0\) \(x+y=8\)
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