JEE Mains · Physics · STD 11 - Fluid mechanics
- JEE Mains 2021
- Hard
- Numerical
A hydraulic press can lift \(100\, kg\) when a mass \('m'\) is placed on the smaller piston. It can lift ......... \(kg\) when the diameter of the larger piston is increased by \(4\) times and that of the smaller piston is decreased by \(4\) times keeping the same mass \('m'\) on the smaller piston.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(25600\)
Step-by-step Solution
Detailed explanation
Using Pascals law
\(\frac{100 \times g }{ A _{2}}=\frac{ mg }{ A _{1}}\) \(........(1)\)
Let \(m\) mass can lift \(M _{0}\) in second case then
\(\frac{ M _{0} g }{16 A _{2}}=\frac{ mg }{ A _{1} / 16}\) \(.........(2)\)
\(\left\{\right.\) Since \(\left.A=\frac{\pi d ^{2}}{4}\right\}\)
From equation \((1)\) and \((2)\) we get
\(\frac{ M _{0}}{16.100}=16\)
\(\Rightarrow M _{0}=25600 \,kg\)
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