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JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization

In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ \(\times 10^{-1} \%\).
(Molar mass : \(\mathrm{O}=16, \mathrm{~S}=32, \mathrm{Ba}=137\) in \(\mathrm{g} \mathrm{mol}^{-1}\) )

  1. A 250
  2. B 275
  3. C 300
  4. D 325
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Answer & Solution

Correct Answer

(B) 275

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Detailed explanation

\begin{array}{ll}\text { Organic Compound } \longrightarrow & \mathrm{BaSO}_4 \\ 0.20 \mathrm{gm} & 0.40 \mathrm{gm} \\ & \frac{0.40}{233} \mathrm{~mol}\left(\mathrm{BaSO}_4\right) \\ & \frac{0.40}{233} \mathrm{~mol} \text { (Sulphur) } \\ & \frac{0.40}{233} \times 32…

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