JEE Mains · Physics · STD 11 - 11. thermodynamics
\(n\) mole a perfect gas undergoes a cyclic process \(ABCA\) (see figure) consisting of the following processes. \(A \rightarrow B :\) Isothermal expansion at temperature \(T\) so that the volume is doubled from \(V _{1}\) to \(V _{2}=2 V _{1}\) and pressure changes from \(P _{1}\) to \(P _{2}\) \(B \rightarrow C :\) Isobaric compression at pressure \(P _{2}\) to initial volume \(V _{1}\) \(C \rightarrow A\) : Isochoric change leading to change of pressure from \(P _{2}\) to \(P _{1}\) Total workdone in the complete cycle \(ABCA\) is

- A \(0\)
- B \(nRT \left(\ln 2+\frac{1}{2}\right)\)
- C \(nRTIn2\)
- D \(nRT \left(\ln 2-\frac{1}{2}\right)\)
Answer & Solution
Correct Answer
(D) \(nRT \left(\ln 2-\frac{1}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(W _{\text {Isothermal }}= nRT \ln \left(\frac{ v _{2}}{ v _{1}}\right)\) \(W _{\text {Isobaric }}= P \Delta V = nR \Delta T\) \(W _{\text {Isochoric }}=0\) \(W _{1}= nRT \ln \left(\frac{2 V }{ V }\right)= nRT \ln 2\)…
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