JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Consider the following reversible chemical reactions \({A_2}(g)\, + \,{B_2}(g)\,\overset {{K_1}} \leftrightarrows \,2AB(g)\,\,\,......(1)\) \(6AB\,(g)\,\,\overset {{K_2}} \leftrightarrows \,\,3{A_2}(g)\, + \,3{B_2}(g)......(2)\) The relation between \(K_1\) and \(K_2\) is
- A \({K_1}{K_2} = \frac{1}{3}\)
- B \({K_2} = K_1^3\)
- C \({K_2} = K_1^{-3}\)
- D \({K_1}{K_2} = 3\)
Answer & Solution
Correct Answer
(C) \({K_2} = K_1^{-3}\)
Step-by-step Solution
Detailed explanation
\({A_2}(g) + {B_2}(g)\overset {{K_1}} \longleftrightarrow 2AB(g).....(1)\) \(6AB(g)\overset {{K_2}} \longleftrightarrow 3{A_2}(g) + 3{B_2}(g).....(2)\) Reaction \((2) = -3 \times \) reaction \((1)\)…
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