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JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

ठोस गोला \(\mathrm{A}\) अक्ष \(\mathrm{PQ}\) के परितः घूर्णन करता है। यदि गोले की त्रिज्या \(5 \mathrm{~cm}\) हो तब उसकी \(\mathrm{PQ}\) के परितः घूर्णन त्रिज्या \(\sqrt{\mathrm{x}} \mathrm{cm}\) होगी। \(\mathrm{x}\) ___________है।

  1. A \(110\)
  2. B \(55\)
  3. C \(10.48\)
  4. D \(100\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(110\)

Step-by-step Solution

Detailed explanation

\(I _{ cm }=\frac{2}{5} MR ^2\) \(I _{ PQ }= I _{ cm }+ md ^2\) \(I _{ PQ }=\frac{2}{5} mR ^2+ m (10\,cm )^2\) For radius of gyration \(I _{ PQ }= mk ^2\) \(k ^2=\frac{2}{5} R ^2+(10\,cm )^2\) \(=\frac{2}{5}(5)^2+100\) \(=10+100=110\) \(k =\sqrt{110}\,cm\) \(x =110\)
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