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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

इलेक्ट्रॉन की \(\left(\lambda_{e}\right)\), \(\alpha\)-कण की \(\left(\lambda_{\alpha}\right)\) तथा प्रोटॉन की \(\left(\lambda_{ p }\right)\) की दे-ब्राग्ली तरंगदैधर्यों का क्रम क्या होगा? दिया है कि सभी की गतिज ऊर्जा समान है ?

  1. A \(\lambda_{{e}}\,=\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)
  2. B \(\lambda_{{e}}\,=\,\lambda_{{p}}\,=\,\lambda_{\alpha}\)
  3. C \(\lambda_{{e}}\,>\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)
  4. D \(\lambda_{{e}}\,<\,\lambda_{{p}}\,<\,\lambda_{\alpha}\)
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Answer & Solution

Correct Answer

(C) \(\lambda_{{e}}\,>\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{ h }{ p }=\frac{ h }{\sqrt{2 mE }} \propto \frac{1}{\sqrt{ m }}\) \(m _{\alpha}> m _{ p }> m _{e}\) \(\lambda_{e}>\lambda_{p}>\lambda_{\alpha}\)
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