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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2021
  • Medium
  • MCQ

What should be the order of arrangement of de-Broglie wavelength of elelctron \(\left(\lambda_{{e}}\right)\), an \(\alpha-\) particle \(\left(\lambda_{\alpha}\right)\) and proton \(\left(\lambda_{p}\right)\) given that all have the same kinetic energy ?

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Answer & Solution

Correct Answer

(C) \(\lambda_{{e}}\,>\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{ h }{ p }=\frac{ h }{\sqrt{2 mE }} \propto \frac{1}{\sqrt{ m }}\)

\(m _{\alpha}> m _{ p }> m _{e}\)

\(\lambda_{e}>\lambda_{p}>\lambda_{\alpha}\)

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