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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
What should be the order of arrangement of de-Broglie wavelength of elelctron \(\left(\lambda_{{e}}\right)\), an \(\alpha-\) particle \(\left(\lambda_{\alpha}\right)\) and proton \(\left(\lambda_{p}\right)\) given that all have the same kinetic energy ?
- A \(\lambda_{{e}}\,=\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)
- B \(\lambda_{{e}}\,=\,\lambda_{{p}}\,=\,\lambda_{\alpha}\)
- C \(\lambda_{{e}}\,>\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)
- D \(\lambda_{{e}}\,<\,\lambda_{{p}}\,<\,\lambda_{\alpha}\)
Answer & Solution
Correct Answer
(C) \(\lambda_{{e}}\,>\,\lambda_{{p}}\,>\,\lambda_{\alpha}\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{ h }{ p }=\frac{ h }{\sqrt{2 mE }} \propto \frac{1}{\sqrt{ m }}\) \(m _{\alpha}> m _{ p }> m _{e}\) \(\lambda_{e}>\lambda_{p}>\lambda_{\alpha}\)
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