\({ }_{92}^{235} U\) नाभिक के प्रति विखंडन औसत ऊर्जा 190 MeV है। जब 47 g शुद्ध \({ }_{92}^{235} U\) के सभी परमाणु विखंडन प्रक्रिया से गुजरते हैं, तो उत्सर्जित ऊर्जा \(\alpha \times 10^{23} MeV\) है। \(\alpha\) का मान ___________ है।
(आवोगाद्रो संख्या \(=6 \times 10^{23}\) प्रति मोल)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.