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JEE Mains · Physics · STD 11 - 3.2 motion in plane

ઉદગમ સ્થાનથી \(t = 0\) સમયે ફેંકેલ પદાર્થ નું સ્થાન \(t = 2\,s\) સમયે \(\vec r = \left( {40\hat i + 50\hat j} \right)\,m\)  છે. જો પદાર્થને સમક્ષિતિજથી \(\theta\) કોણે ફેંકવામાં આવ્યો હોય તો \(\theta\) શું હશે?  (\(g = 10\, ms^{-2}\))

  1. A \({\tan ^{ - 1}}\frac{2}{3}\)
  2. B \({\tan ^{ - 1}}\frac{3}{2}\)
  3. C \({\tan ^{ - 1}}\frac{7}{4}\)
  4. D \({\tan ^{ - 1}}\frac{4}{5}\)
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Correct Answer

(C) \({\tan ^{ - 1}}\frac{7}{4}\)

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\begin{array}{l} \,\,\,\,\,\,\,\,\,From\,question,\\ \,\,\,\,\,\,\,\,\,Horizontal\,velocity\,\left( {initial} \right),\\ \,\,\,\,\,\,\,\,\,{u_x} = \frac{{40}}{2} = 20m/s\\ \,\,\,\,\,\,\,\,\,Vertical\,velocity\,\left( {initial} \right),\\ \,\,\,\,\,\,\,\,\,\,50 = {u_y}t +…

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