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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

જો \(\varepsilon_0\) શૂન્યાવકાશની પરમિટિવિટી હોય અને \(E\) વિદ્યુત ક્ષેત્ર હોય, તો \(\varepsilon_0 E^2\) ના પરિમાણો _______ છે.

  1. A \(\left[\mathrm{M}^0 \mathrm{~L}^{-2} \mathrm{TA}\right]\)
  2. B \(\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\)
  3. C \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^4 \mathrm{~A}^2\right]\)
  4. D \(\left[\mathrm{M} \mathrm{L}^2 \mathrm{~T}^{-2}\right]\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\)

Step-by-step Solution

Detailed explanation

\(\mathrm{E}=\frac{\mathrm{K}}{\mathrm{R}^2}\) \(\mathrm{E}=\frac{\mathrm{Q}}{4 \pi \varepsilon_0 \mathrm{R}^2}\) \(\varepsilon_0=\frac{\mathrm{Q}}{4 \pi \mathrm{R}^2 \mathrm{E}}\) હવે,…
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