ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Physics · STD 12 - 13. Nuclei

હાઇડ્રોજન બોમ્બ માં વિસ્ફોટકો \({ }_1 \mathrm{H}^2,{ }_1 \mathrm{H}^3\) અને \({ }_3 \mathrm{Li}^6\) કોઇક સંધટિત મિશ્રણના સ્વરૂપે છે. શૃંખલા પ્રક્રિયાને \({ }_3 \mathrm{Li}^6+{ }_0 \mathrm{n}^1 \rightarrow{ }_2 \mathrm{He}^4+{ }_1 \mathrm{H}^3\)અને \({ }_1 \mathrm{H}^2+{ }_1 \mathrm{H}^3 \rightarrow{ }_2 \mathrm{He}^4+{ }_0 \mathrm{n}^1\) વડે દર્શાવવામાં આવે છે. વિસ્ફોટ દરમિયાન અંદાજે______ઊર્જા મુક્ત થાય છે. [Given : \(\mathrm{M}(\mathrm{Li})=6.01690\  \mathrm{amu} . \mathrm{M}\left({ }_1 \mathrm{H}^2\right)=2.01471 \  amu.\) \(\mathrm{M}\left({ }_2 \mathrm{He}^4\right)=4.00388\  \mathrm{amu}\),\( and\ \)\(1 \ \mathrm{amu}=931.5\) \(\mathrm{MeV}]\)

  1. A  \(28.12\  \mathrm{MeV}\)
  2. B  \(12.64\  \mathrm{MeV}\)
  3. C  \(16.48\ \mathrm{MeV}\)
  4. D  \(22.22\  \mathrm{MeV}\)
Verified Solution

Answer & Solution

Correct Answer

(D)  \(22.22\  \mathrm{MeV}\)

Step-by-step Solution

Detailed explanation

\( { }_3 \mathrm{Li}^6+{ }_0 \mathrm{n}^1 \rightarrow{ }_2 \mathrm{He}^4+{ }_1 \mathrm{H}^3 \) \( { }_1 \mathrm{H}^2+{ }_1 \mathrm{H}^3 \rightarrow{ }_2 \mathrm{He}^4+{ }_0 \mathrm{n}^1\) --------------------------------------------------------------…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app