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JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

સૂચી \(-I\) સાથે સુચી\(-II\) ને જોડો.
સૂચી \(-I\) (અણુ) સૂચી \(-II\) (બંધ ક્રમાંક)
\((a)\) \(Ne _{2}\) \((i)\) \(1\)
\((b)\) \(N _{2}\) \((ii)\) \(2\)
\((c)\) \(F _{2}\) \((iii)\) \(0\)
\((d)\) \(O _{2}\) \((iv)\) \(3\)
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.

  1. A \(( a ) \rightarrow( iii ),( b ) \rightarrow( iv ),( c ) \rightarrow( i ),( d ) \rightarrow( ii )\)
  2. B \(( a ) \rightarrow( i ),( b ) \rightarrow( ii ),( c ) \rightarrow( iii ),( d ) \rightarrow( iv )\)
  3. C \(( a ) \rightarrow( ii ),( b ) \rightarrow( i ),( c ) \rightarrow( iv ),( d ) \rightarrow( iii )\)
  4. D \(( a ) \rightarrow( iv ),( b ) \rightarrow( iii ),( c ) \rightarrow( ii ),( d ) \rightarrow( i )\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(( a ) \rightarrow( iii ),( b ) \rightarrow( iv ),( c ) \rightarrow( i ),( d ) \rightarrow( ii )\)

Step-by-step Solution

Detailed explanation

\((a)\) \(\quad Ne _{2}=\operatorname{Total} e ^{\Theta}=20\) B.O. \(=\frac{10-10}{2}=0\) \((b)\) \(\quad N _{2}=\) Total \(e ^{\Theta}=14\) B.O. \(=\frac{10-4}{2}=3\) \((c)\) \(\quad F _{2}=\) Total \(e ^{\Theta}=18\) B.O. \(=\frac{10-8}{2}=1\) (d)…
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