JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Match List\(-I\) with List\(-II.\)
| List\(-I\) | List\(-II\) |
| \((a)\) \(Ne _{2}\) | \((i)\) \(1\) |
| \((b)\) \(N _{2}\) | \((ii)\) \(2\) |
| \((c)\) \(F _{2}\) | \((iii)\) \(0\) |
| \((d)\) \(O _{2}\) | \((iv)\) \(3\) |
- A \(( a ) \rightarrow( iii ),( b ) \rightarrow( iv ),( c ) \rightarrow( i ),( d ) \rightarrow( ii )\)
- B \(( a ) \rightarrow( i ),( b ) \rightarrow( ii ),( c ) \rightarrow( iii ),( d ) \rightarrow( iv )\)
- C \(( a ) \rightarrow( ii ),( b ) \rightarrow( i ),( c ) \rightarrow( iv ),( d ) \rightarrow( iii )\)
- D \(( a ) \rightarrow( iv ),( b ) \rightarrow( iii ),( c ) \rightarrow( ii ),( d ) \rightarrow( i )\)
Answer & Solution
Correct Answer
(A) \(( a ) \rightarrow( iii ),( b ) \rightarrow( iv ),( c ) \rightarrow( i ),( d ) \rightarrow( ii )\)
Step-by-step Solution
Detailed explanation
\((a)\) \(\quad Ne _{2}=\operatorname{Total} e ^{\Theta}=20\) B.O. \(=\frac{10-10}{2}=0\) \((b)\) \(\quad N _{2}=\) Total \(e ^{\Theta}=14\) B.O. \(=\frac{10-4}{2}=3\) \((c)\) \(\quad F _{2}=\) Total \(e ^{\Theta}=18\) B.O. \(=\frac{10-8}{2}=1\) (d)…
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