ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

નિર્બળ એસિડ \(\mathrm{HX}\) ના વિયોજનનો વિચાર કરો જે નીચે મુજબ છે: \(\mathrm{HX}(\mathrm{aq}) \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{X}(\mathrm{aq}), \mathrm{Ka}=1.2 \times 10^{-5}\) \(\left[\mathrm{K}_{\mathrm{a}}:\right.\) વિયોજન અચળાંક] \(300 \mathrm{~K}\) તાપમાને \(\mathrm{HX}\) ના \(0.03 \mathrm{M}\) જલીય દ્રાવણનું અભિસરણ દબાણ _______ \(\times 10^{-2}\) બાર (નજીકના પૂર્ણાંકમાં) છે. \(\left[\right.\) આપેલ છે : \(\mathrm{R}=0.083 \mathrm{~L} \mathrm{bar} \mathrm{Mol}^{-1} \mathrm{~K}^{-1}\) ]

  1. A \(76\)
  2. B \(77\)
  3. C \(79\)
  4. D \(80\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(76\)

Step-by-step Solution

Detailed explanation

\(\mathrm{HX} \rightleftharpoons \mathrm{H}^{+}+\mathrm{X}^{-} \quad \mathrm{K}_{\mathrm{a}}=1.2 \times 10^{-5}\) \(0.03 \mathrm{M}\) \(0.03-\mathrm{x} \quad \mathrm{x} \quad \mathrm{x}\) \(\mathrm{K}_{\mathrm{a}}=1.2 \times 10^{-5}=\frac{\mathrm{x}^2}{0.03-\mathrm{x}}\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app