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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(298\; \mathrm{K}\) પર \(\mathrm{Cr}(\mathrm{OH})_{3}\) નો \(K_{sp}=6.0 \times 10^{-31}\) છે. તો \(\mathrm{Cr}(\mathrm{OH})_{3}\) ના સંતૃપ્ત દ્રાવણમાં હાઇડ્રોક્સાઇડ આયનની સાંદ્રતા કેટલી થશે ?

  1. A \(\left(18 \times 10^{-31}\right)^{1 / 4}\)
  2. B \(\left(2.22 \times 10^{-31}\right)^{1 / 4}\)
  3. C \(\left(4.86 \times 10^{-29}\right)^{1 / 4}\)
  4. D \(\left(18 \times 10^{-31}\right)^{1 / 2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(18 \times 10^{-31}\right)^{1 / 4}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{Cr}(\mathrm{OH})_{3}(\mathrm{s}) \rightleftharpoons \mathrm{Cr}^{3+}(\mathrm{aq} .)+3 \mathrm{OH}^{-}(\mathrm{aq} .)\) \(\mathrm{k}_{\mathrm{sp}}=27(\mathrm{s})^{4}=6 \times 10^{-31}\) \(\Rightarrow[3(\mathrm{s})]^{4}=18 \times 10^{-31}\)…
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