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JEE Mains · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes

નીચેની પ્રક્રિયા શ્રેણીમાં સંયોજન \(I\) શુ હશે ?  \(\mathop I\limits_{({C_3}{H_6}C{l_2})} \xrightarrow{{KOH(aq)}}II\xrightarrow[{(ii){H_2}O/{H^ + }}]{{(i)C{H_3}MgBr}}III\xrightarrow{{Anhy.ZnC{l_2} + Conc.HCl}}\)  તરત જ terbidity મળે છે

  1. A \(\begin{array}{*{20}{c}}
      {C{H_2} - CH - C{H_3}} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {Cl\,\,\,\,\,\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}\)
  2. B \(\begin{array}{*{20}{c}}
      {C{H_2} - C{H_2} - C{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
     {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}\)
  3. C \(\begin{array}{*{20}{c}}
      {CH - CH - C{H_2} - C{H_3}} \\ 
      {\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}\)
  4. D \(\begin{array}{*{20}{c}}   {Cl} \\    | \\    {C{H_3} - C - C{H_3}} \\    | \\    {Cl}  \end{array}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\begin{array}{*{20}{c}}   {Cl} \\    | \\    {C{H_3} - C - C{H_3}} \\    | \\    {Cl}  \end{array}\)

Step-by-step Solution

Detailed explanation

\(\underset{(I)}{\mathop{\underset{({{C}_{3}}{{H}_{6}}C{{l}_{2}})}{\mathop{\begin{matrix} \begin{matrix} \,\,Cl \\ | \\ \end{matrix} \\ {{H}_{3}}C-C-C{{H}_{3}} \\ | \\ \,\,Cl \\ \end{matrix}}}\,}}\,\) \(\xrightarrow[{(aq.)}]{{KOH}}\)…
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