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JEE Mains · Chemistry · STD 11 - 2. structure of atom

નીચે \(4\) ઈલેકટ્રોનોનાં ક્વોન્ટમ આંક આપેલા છે. \(A. \;n =3, l=2, m _{1}=1, m _{ s }=+1 / 2\) \(B.\; n =4, l=1, m _{1}=0, m _{ s }=+1 / 2\) \(C. \;n =4, l=2, m _{1}=-2, m _{ s }=-1 / 2\) \(D. \;n =3, l=1, m _{1}=-1, m _{ s }=+1 / 2\) વધતી ઊર્જાનો સાચો ક્રમ શોધો.

  1. A \(D < B < A < C\)
  2. B \(D < A < B < C\)
  3. C \(B < D < A < C\)
  4. D \(B < D < C < A\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(D < A < B < C\)

Step-by-step Solution

Detailed explanation

Energy order of subshell decided by \(( n +\lambda)\) rule. \(A \Rightarrow 3 d \Rightarrow n +1=5\) \(B \Rightarrow 4 p \Rightarrow n +\lambda=5\) \(C \Rightarrow 4 d \Rightarrow n +\ell \Rightarrow 6\) \(D \Rightarrow 3 s \Rightarrow( n +\ell)=4\) \(D < A < B < C\)
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