JEE Mains · Chemistry · STD 11 - 2. structure of atom
Given below are the quantum numbers for \(4\) electrons. \(A. \;n =3, l=2, m _{1}=1, m _{ s }=+1 / 2\) \(B.\; n =4, l=1, m _{1}=0, m _{ s }=+1 / 2\) \(C. \;n =4, l=2, m _{1}=-2, m _{ s }=-1 / 2\) \(D. \;n =3, l=1, m _{1}=-1, m _{ s }=+1 / 2\) The correct order of increasing energy is
- A \(D < B < A < C\)
- B \(D < A < B < C\)
- C \(B < D < A < C\)
- D \(B < D < C < A\)
Answer & Solution
Correct Answer
(B) \(D < A < B < C\)
Step-by-step Solution
Detailed explanation
Energy order of subshell decided by \(( n +\lambda)\) rule. \(A \Rightarrow 3 d \Rightarrow n +1=5\) \(B \Rightarrow 4 p \Rightarrow n +\lambda=5\) \(C \Rightarrow 4 d \Rightarrow n +\ell \Rightarrow 6\) \(D \Rightarrow 3 s \Rightarrow( n +\ell)=4\) \(D < A < B < C\)
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