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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(20\, mL \,0.1\, M\, NH _4 OH\) ને \(40\, mL \,0.05 \,M\, HCl\) સાથે મિશ્ર કરવામાં આવ્યો. તો આ મિશ્રણની \(.....\,pH\) છે. (આપેલ : \(K _{ b }\left( NH _4 OH \right)=1 \times 10^{-5}, \log 2=0.30, \log 3=0.48, \log 5=0.69, \log 7=0.84, \log 11=\) \(1.04)\)

  1. A \(3.2\)
  2. B \(4.2\)
  3. C \(5.2\)
  4. D \(6.2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5.2\)

Step-by-step Solution

Detailed explanation

\(NH _{4} OH + HCl \rightarrow NH _{4} Cl + H _{2} O\) \(\left[ NH _{4}^{+}\right]=\frac{2\,m\,mole }{60\,ml }=\frac{1}{30}\,M\) \(pH =\frac{ pK _{ w }- pK _{ b }-\log C }{2}=\frac{14-5+1.48}{2}=5.24\)
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