JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
\(20\,mL\) of \(0.1\,M\,NH _{4} OH\) is mixed with \(40\,mL\) of \(0.05\,M\,HCl\). The \(pH\) of the mixture is nearest to.(Given: \(K _{ b }\left( NH _{4} OH \right)=1 \times 10^{-5}, \log 2=0.30\),\(\log 3=0.48, \log 5=0.69, \log 7=0.84\),\(\log 11=1.04)\)
- A \(3.2\)
- B \(4.2\)
- C \(5.2\)
- D \(6.2\)
Answer & Solution
Correct Answer
(C) \(5.2\)
Step-by-step Solution
Detailed explanation
\(NH _{4} OH + HCl \rightarrow NH _{4} Cl + H _{2} O\) \(\left[ NH _{4}^{+}\right]=\frac{2\,m\,mole }{60\,ml }=\frac{1}{30}\,M\) \(pH =\frac{ pK _{ w }- pK _{ b }-\log C }{2}=\frac{14-5+1.48}{2}=5.24\)
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