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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(0.050\,M\,Ba \left( NO _3\right)_2\) ના \(25.0\,mL\) ને \(0.020\,M,NaF\),ના \(25.0\,mL\) સાથે મિશ્ર કરવામાં આવે છે.\(298\,K\) પર \(BaF _2\) ની \(Ksp\, 0.5 \times 10^{-6}\) છે.\(\left[ Ba ^{2+}\right]\left[ F ^{-}\right]^2\) અને \(Ksp\) નો ગુણોત્તર \(........\) છે.

  1. A \(2\)
  2. B \(3\)
  3. C \(5\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

\({\left[ Ba ^{+2}\right]=\frac{25 \times 0.05}{50}=0.025 M }\) \({\left[ F ^{-}\right]=\frac{25 \times 0.02}{50}=0.01 M }\) \({\left[ Ba ^{+2}\right]\left[ F ^{-}\right]^2=25 \times 10^{-7}}\) \(K _{ sp }=5 \times 10^{-7} \text { (given) }\)…
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