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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

એક કાર્બનિક સંયોજનનું સંપૂર્ણ દહન કરતાં તે \(0.220\,g\,CO _2\) અને \(0.126\,g\,H _2 O\) આપે છે.જો કાર્બનના \(\%\) એ \(24 \%\) હોય તો પછી હાઈડ્રોજનના \(\%\) \(........\,\times 10^{-1}\) છે.(નજીકનો પૂર્ણાક)

  1. A \(51\)
  2. B \(52\)
  3. C \(56\)
  4. D \(53\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(56\)

Step-by-step Solution

Detailed explanation

Moles of \(CO _2=\frac{0.22}{44}=\frac{1}{200}\) \(\therefore\) Moles of carbon \(=\left(\text { Moles of } CO _2\right) \times 1\) \(=\frac{1}{200}\) \(\therefore\) wt. of \(C =\frac{1}{200} \times 12=0.06\) \(\text { \% of } C =\frac{0.06}{ W } \times 100=24\)…
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