JEE Mains · Physics · STD 12 -6. Electromagnetic induction
Two coils \(P\) and \(Q\) are separated by some distance. When a current of \(3\, A\) flows through coil \(P\) a magnetic flux of \(10^{-3}\, Wb\) passes through \(Q\). No current is passed through \(Q\). When no current passes through \(P\) and a current of \(2\, A\) passes through \(Q\), the flux through \(P\) is
- A \(6.67 \times {10^{ - 3}}\,Wb\)
- B \(6.67 \times {10^{ - 4}}\,Wb\)
- C \(3.67 \times {10^{ - 4}}\,Wb\)
- D \(3.67 \times {10^{ - 3}}\,Wb\)
Answer & Solution
Correct Answer
(B) \(6.67 \times {10^{ - 4}}\,Wb\)
Step-by-step Solution
Detailed explanation
Mutual induction \(\phi_{q}=M l_{p}\) \(10^{-3}=\mathrm{M}(3)\) \(\Rightarrow M=\frac{1}{3} \times 10^{-3}\) \(\phi_{\mathrm{p}}=\mathrm{Ml}_{\mathrm{q}}\) \(\Rightarrow \phi_{p}=6.67 \times 10^{-4}\, \mathrm{Wb}\)
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