JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
An expression of energy density is given by \(u=\frac{\alpha}{\beta} \sin \left(\frac{\alpha x}{k t}\right)\), where \(\alpha, \beta\) are constants, \(x\) is displacement, \(k\) is Boltzmann constant and \(t\) is the temperature. The dimensions of \(\beta\) will be.
- A \(\left[ ML ^{2} T ^{-2} \theta^{-1}\right]\)
- B \(\left[ M ^{0} L ^{2} T ^{-2}\right]\)
- C \(\left[ M ^{0} L ^{0} T ^{0}\right]\)
- D \(\left[ M ^{0} L ^{2} T ^{0}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[ M ^{0} L ^{2} T ^{0}\right]\)
Step-by-step Solution
Detailed explanation
\(\frac{\alpha[ L ]}{\left[ ML ^{2} T ^{-2}\right]}=\left[ M ^{0} L ^{0} T ^{0}\right]\) \(\alpha=\left[ ML ^{1} T ^{-2}\right]\)…
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