JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
Consider a rectangular sheet of solid material of length \(\ell=9 \mathrm{~cm}\) and width \(\mathrm{d}=4 \mathrm{~cm}\). The coefficient of linear expansion is \(\alpha=3.1 \times 10^{-5} \mathrm{~K}^{-1}\) at room temperature and one atmospheric pressure. The mass of sheet \(\mathrm{m}=0.1 \mathrm{~kg}\) and the specific heat capacity \(\mathrm{C}_{\mathrm{v}}=900 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}\). If the amount of heat supplied to the material is \(8.1 \times 10^2 \mathrm{~J}\) then change in area of the rectangular sheet is :-
- A \(2.0 \times 10^{-6} \mathrm{~m}^2\)
- B \(3.0 \times 10^{-7} \mathrm{~m}^2\)
- C \(6.0 \times 10^{-7} \mathrm{~m}^2\)
- D \(4.0 \times 10^{-7} \mathrm{~m}^2\)
Answer & Solution
Correct Answer
(A) \(2.0 \times 10^{-6} \mathrm{~m}^2\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{Q}=\mathrm{ms} \Delta \mathrm{T} \\ & 8.1 \times 10^2=0.1 \times 900 \times \Delta \mathrm{T} \\ & \Delta \mathrm{A}=\mathrm{A}_0 2 \alpha \Delta \mathrm{~T}=2.0 \times 10^{-6} \mathrm{~m}^2\end{aligned}\)
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