A hanging mass \(M\) is connected to a four times bigger mass by using a string-pulley arrangement. as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by \(2\,Mg\) force. In this situation. tension in the string is \(\frac{x}{5}\) \(Mg\) for \(x =\) Neglect mass of the string and friction of the block (bigger mass) with ice slab. (Given \(g=\) acceleration due to gravity)

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Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

Using \(\overrightarrow{ F }_{\text {net }}=\mu \vec{a}\)

\(2 Mg - T =4 Ma\)

\(T - Mg = Ma\)

_______________

\(\Rightarrow a =\frac{ g }{5}\)

\(T = Mg + Ma = Mg +\frac{ Mg }{5}=\frac{6}{5}\,Mg\)

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