JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A particle of charge \(1.6 \mu \mathrm{C}\) and mass \(16 \mu \mathrm{~g}\) is present in a strong magnetic field of 6.28 T. The particle is then fired perpendicular to magnetic field. The time required for the particle to return to original location for the first time is ________ S. \((\pi=3.14)\)
- A 5
- B 4
- C 3
- D \(0\)
Answer & Solution
Correct Answer
(D) \(0\)
Step-by-step Solution
Detailed explanation
Angle between \(\overrightarrow{\mathrm{V}}\) of charge \(\& \overrightarrow{\mathrm{~B}}\) is \(90^{\circ}\) motion will be uniform circular motion time period is given by…
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