JEE Mains · Physics · STD 12 -6. Electromagnetic induction
There are two long co -axial solenoids of same length \(l.\) The inner and outer coils have radii \(r_1\) and \(r_2\) and number of turns per unit length \(n_1\) and \(n_2\) respectively. The ratio of mutual inductance to the self -inductance of the inner -coil is
- A \(\frac{{{n_1}}}{{{n_2}}}\)
- B \(\frac{{{n_2}}}{{{n_1}}}.\frac{{{r_1}}}{{{r_2}}}\)
- C \(\frac{{{n_2}}}{{{n_1}}}.\frac{{r_2^2}}{{r_1^2}}\)
- D \(\frac{{{n_2}}}{{{n_1}}}\)
Answer & Solution
Correct Answer
(D) \(\frac{{{n_2}}}{{{n_1}}}\)
Step-by-step Solution
Detailed explanation
\(\ \frac{M}{L} =\frac{\mu_{0} n n_{1} n_{2} n_{1}^{2} \ell}{\mu_{0} \pi n_{1}^{2} r_{1}^{2} \ell}\) \(=\frac{n_{2}}{n_{1}}\)
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