JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A coil of cross-sectional area \(A\) having \(n\) turns is placed in a uniform magnetic field \(B.\) When it is rotated with an angular velocity \(\omega ,\) the maximum \(e.m.f.\) induced in the coil will be
- A \(nBA\omega \)
- B \(\frac{3}{2}\,nBA\omega \)
- C \(3\,nBA\omega \)
- D \(\frac{1}{2}\,nBA\omega \)
Answer & Solution
Correct Answer
(A) \(nBA\omega \)
Step-by-step Solution
Detailed explanation
Induced emf in a coil, \(e\, = \, - \frac{{d\phi }}{{dt}}\, = \,NBA\,\omega \,\sin \,\,\omega t\) Also, \(e = e_0\,\,sin\,\omega t\) \(\therefore \) Maximum \(emf\) induced, \(e_0 = nBA\omega \)
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