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JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2018
  • Medium
  • MCQ

A coil of cross-sectional area  \(A\) having \(n\)  turns is placed in a uniform magnetic field \(B.\)  When it is rotated with an angular velocity \(\omega ,\)  the maximum \(e.m.f.\)  induced in the coil will be

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Answer & Solution

Correct Answer

(A) \(nBA\omega \)

Step-by-step Solution

Detailed explanation

Induced emf in a coil,

\(e\, = \, - \frac{{d\phi }}{{dt}}\, = \,NBA\,\omega \,\sin \,\,\omega t\)

Also, \(e = e_0\,\,sin\,\omega t\)

\(\therefore \)  Maximum \(emf\)  induced, \(e_0 = nBA\omega \)

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