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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2022
  • Easy
  • MCQ

A long straight wire with a circular crosssection having radius \(R\), is carrying a steady current \(I\). The current I is uniformly distributed across this cross-section. Then the variation of magnetic field due to current I with distance \(r\;( r < R )\) from its centre will be

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Answer & Solution

Correct Answer

(B) \(B \propto r\)

Step-by-step Solution

Detailed explanation

Use Ampere's law

\(\text { B. } 2 \pi r =\mu_{0} \cdot \frac{ I }{\pi R ^{2}} \cdot \pi r ^{2}\)

Thus \(B \propto r\)

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