JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A square loop \(\mathrm{PQRS}\) having \(10\) turns, area \(3.6 \times\) \(10^{-3} \mathrm{~m}^2\) and resistance \(100 \Omega\) is slowly and uniformly being pulled out of a uniform magnetic field of magnitude \(\mathrm{B}=0.5 \mathrm{~T}\) as shown. Work done in pulling the loop out of the field in \(1.0 \mathrm{~s}\) is _______ \(\times 10^{-6} \mathrm{~J}\).
- A \(2\)
- B \(1\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(\epsilon=N B \ell v\) \(i=\frac{\epsilon}{R}=\frac{N B \ell v}{R}\) \(F=N(i \ell B)=\frac{N^2 B^2 \ell^2 v}{R}\) \(\mathrm{W}=\mathrm{F} \times \ell=\frac{\mathrm{N}^2 \mathrm{~B}^2 \ell^3}{\mathrm{R}}\left(\frac{\ell}{\mathrm{t}}\right)\) \(\mathrm{A}=\ell^2\)…
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