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JEE Mains · Physics · STD 12 - 10. Wave optics
A ray of light of intensity \(I\) is incident on a parallel glass slab at point \(A\) as shown in diagram. It undergoes partial reflection and refraction. At each reflection, \(25\%\) of incident energy is reflected. The rays \(AB\) and \(A'B'\) undergo interference. The ratio of \(I_{max}\) and \(I_{min}\) is

- A \(49: 1\)
- B \(7 : 1\)
- C \(4 : 1\)
- D \(8 : 1\)
Answer & Solution
Correct Answer
(A) \(49: 1\)
Step-by-step Solution
Detailed explanation
\(\frac{{{I_{\max }}}}{{{I_{\min }}}} = {\left( {\frac{{\sqrt {{I_1}} + \sqrt {{I_2}} }}{{\sqrt {{I_1}} - \sqrt {{I_2}} }}} \right)^2}\) \({I_1} = \frac{I}{4}:{I_2} = \frac{{91}}{{64}}\) \(\frac{{{I_{\max }}}}{{{I_{\min }}}}=\frac{{49}}{1}\)
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