JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A man grows into a giant such that his linear dimensions increase by a factor of \(9\). Assuming that his density remains same, the stress in the leg will change by a factor of
- A \(9\)
- B \(\frac{1}{9}\)
- C \(81\)
- D \(\frac{1}{{81}}\)
Answer & Solution
Correct Answer
(A) \(9\)
Step-by-step Solution
Detailed explanation
As liner dimension increases by a factor of \(9\) \(\frac{{{v_f}}}{{{v_i}}} = {9^3}\) Density remains same So, mass \(\propto\) Volume \(\frac{{{m_f}}}{{{m_i}}} = {9^3}\,\,\, \Rightarrow \,\,\,\frac{{{{\left( {Aera} \right)}_f}}}{{{{\left( {Aera} \right)}_i}}} = {9^2}\)…
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