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JEE Mains · Physics · STD 11 - 11. thermodynamics

Initial pressure and volume of a monoatomic ideal gas are \(P\) and \(V\). The change in internal energy of this gas in adiabatic expansion to volume \(V_{final}=27V\) is ________ J.

  1. A \(-2PV(3\sqrt{3}-1)\)
  2. B \(\dfrac{4}{3}PV\)
  3. C \(-\dfrac{4}{3}PV\)
  4. D \(\dfrac{3}{4}PV\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\dfrac{4}{3}PV\)

Step-by-step Solution

Detailed explanation

For a monoatomic ideal gas, the ratio of specific heats is \(\gamma = \dfrac{5}{3}\). In an adiabatic process, \(PV^{\gamma} = \text{constant}\). \(P_1 V_1^{\gamma} = P_2 V_2^{\gamma}\) \(P V^{5/3} = P_2 (27V)^{5/3}\) \(P_2 = P \left(\dfrac{1}{27}\right)^{5/3} = \dfrac{P}{243}\)…
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