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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2021
  • Hard
  • MCQ

If force \(({F})\), length \(({L})\) and time \(({T})\) are taken as the fundamental quantities. Then what will be the dimension of density

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Answer & Solution

Correct Answer

(A) \(\left[{FL}^{-4} {T}^{2}\right]\)

Step-by-step Solution

Detailed explanation

\(\text { Density }=\left[{F}^{{a}} {L}^{{b}} {T}^{{c}}\right]\)

\({\left[{ML}^{-3}\right]=\left[{M}^{{a}} {L}^{{a}} {T}^{-2 {a}} {L}^{{b}} {T}^{{c}}\right]}\)

\({\left[{M}^{1} {L}^{-3}\right]=\left[{M}^{{a}} {L}^{{a}+{b}} {T}^{-2 {a}+c}\right]}\)

\({a}=1 ; \quad {a}+{b}=-3 \quad ; \quad-2 {a}+{c}=0\)

\(\quad 1+{b}=-3 \quad {c}=2 {a}\)

\({b}=-4 \quad {c}=2\)

So, density \(=\left[{F}^{1} {L}^{-4} {T}^{2}\right]\)

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