JEE Mains · Physics · STD 11 - 11. thermodynamics
One mole of an ideal diatomic gas expands from volume V to 2 V isothermally at a temperature \(27^{\circ} C\) and does W joule of work. If the gas undergoes same magnitude of expansion adiabatically from \(27^{\circ} C\) doing the same amount of work W , then its final temperature will be (close to) ___________ \({ }^{\circ} C\).
- A \(-189\)
- B \(-56\)
- C \(-30\)
- D \(-117\)
Answer & Solution
Correct Answer
(B) \(-56\)
Step-by-step Solution
Detailed explanation
For Isothermal process \(W _{\text {isothermal }}= nRT \ell n \left(\frac{ V _2}{V_1}\right)\) \(=1 . R 300 . \ell n (2)\) \(=300 R(0.693)\)............(1) Now for adiabatic process, It is given work done in Isothermal = work done in adiabatic…
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