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JEE Mains · Physics · STD 11 - 11. thermodynamics

One mole of an ideal diatomic gas expands from volume V to 2 V isothermally at a temperature \(27^{\circ} C\) and does W joule of work. If the gas undergoes same magnitude of expansion adiabatically from \(27^{\circ} C\) doing the same amount of work W , then its final temperature will be (close to) ___________ \({ }^{\circ} C\).

  1. A \(-189\)
  2. B \(-56\)
  3. C \(-30\)
  4. D \(-117\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-56\)

Step-by-step Solution

Detailed explanation

For Isothermal process \(W _{\text {isothermal }}= nRT \ell n \left(\frac{ V _2}{V_1}\right)\) \(=1 . R 300 . \ell n (2)\) \(=300 R(0.693)\)............(1) Now for adiabatic process, It is given work done in Isothermal = work done in adiabatic…
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